What is the integral from 1 to 9 of sqrt(x) ?

The integral from 1 to 9 of sqrt(x) is 52/3

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integral from 1 to 9 of sqrt(x)

\int_{1}^{9} x d x

\frac{52}{3}

Decimal Notation

17.33333 \dots

Solution steps

\int_{1}^{9} x d x

Apply the Power Rule

: [\frac{2}{3} x^{\frac{3}{2}}]_{1}^{9}

= [\frac{2}{3} x^{\frac{3}{2}}]_{1}^{9}

Compute the boundaries:

\frac{52}{3}

= \frac{52}{3}

\int (\frac{1}{cos ( 4 x )})^{2} d x

y^{'} = 0.0012 y (1000 - y)

\int 2 e^{2 θ} sin (2 θ) d θ

3 x^{\frac{3}{8}}

\frac{d}{d x} (x e^{x} + x)

What is the integral from 1 to 9 of sqrt(x) ?
The integral from 1 to 9 of sqrt(x) is 52/3