What is the tangent of f(x)=3x^2,\at x=10 ?

The tangent of f(x)=3x^2,\at x=10 is y=60x-300

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tangent of f(x)=3x^2,\at x=10

tangent of

f (x) = 3 x^{2}, at x = 10

y = 60 x - 300

Solution steps

Find the tangent point:

(10, 300)

Find the slope of

f (x) = 3 x^{2} : \frac{df ( x )}{d x} = 6 x

Compute the slope of

f (x) = 3 x^{2}

x = 10 : m = 60

Find the line with slope m=

60

and passing through

(10, 300) : y = 60 x - 300

y = 60 x - 300

\int_{1}^{10} \frac{37}{x ^{3}} d x

\frac{d}{d x} (ln (\frac{2 x + 1}{2 x - 1}))

x \to a lim (1 - 1 - x^{2})

\frac{d y}{d x} = e^{(6 y + 3 x)}

\int (x^{4} - 2 x) d x

What is the tangent of f(x)=3x^2,\at x=10 ?
The tangent of f(x)=3x^2,\at x=10 is y=60x-300