What is the tangent of f(x)=7x-4sqrt(x),\at x=1 ?

The tangent of f(x)=7x-4sqrt(x),\at x=1 is y=5x-2

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tangent of f(x)=7x-4sqrt(x),\at x=1

tangent of

f (x) = 7 x - 4 x, at x = 1

y = 5 x - 2

Solution steps

Find the tangent point:

(1, 3)

Find the slope of

f (x) = 7 x - 4 x : \frac{df ( x )}{d x} = 7 - \frac{2}{x}

Compute the slope of

f (x) = 7 x - 4 x

x = 1 : m = 5

Find the line with slope m=

5

and passing through

(1, 3) : y = 5 x - 2

y = 5 x - 2

g (x) = 9 x e^{5 x}

\int - 5 x^{3} + \frac{3}{4} x^{2} d x

\frac{d}{d x} ((e^{- x} - e^{5}) (e^{x} + e^{- 2}))

f (x) = \frac{5 x}{( 1 + x ^{2} )}

\frac{2 x}{( x + 1 ) ^{2}}

What is the tangent of f(x)=7x-4sqrt(x),\at x=1 ?
The tangent of f(x)=7x-4sqrt(x),\at x=1 is y=5x-2