What is the derivative of f(x)=(5x)/((1+x^2)) ?

The derivative of f(x)=(5x)/((1+x^2)) is (5(1-x^2))/((1+x^2)^2)

What is the first derivative of f(x)=(5x)/((1+x^2)) ?

The first derivative of f(x)=(5x)/((1+x^2)) is (5(1-x^2))/((1+x^2)^2)

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derivative of

f (x) = \frac{5 x}{( 1 + x ^{2} )}

\frac{5 ( 1 - x ^{2} )}{( 1 + x ^{2} ) ^{2}}

Solution steps

\frac{d}{d x} (\frac{5 x}{1 + x ^{2}})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 5 \frac{d}{d x} (\frac{x}{1 + x ^{2}})

Apply the Quotient Rule:

(\frac{f}{g})^{'} = \frac{f ^{'} \cdot g - g ^{'} \cdot f}{g ^{2}}

= 5 \cdot \frac{\frac{d x}{d x} ( 1 + x ^{2} ) - \frac{d}{d x} ( 1 + x ^{2} ) x}{( 1 + x ^{2} ) ^{2}}

\frac{d x}{d x} = 1

\frac{d}{d x} (1 + x^{2}) = 2 x

= 5 \cdot \frac{1 \cdot ( 1 + x ^{2} ) - 2 xx}{( 1 + x ^{2} ) ^{2}}

Simplify

5 \cdot \frac{1 \cdot ( 1 + x ^{2} ) - 2 xx}{( 1 + x ^{2} ) ^{2}} : \frac{5 ( 1 - x ^{2} )}{( 1 + x ^{2} ) ^{2}}

= \frac{5 ( 1 - x ^{2} )}{( 1 + x ^{2} ) ^{2}}

\frac{2 x}{( x + 1 ) ^{2}}

\int x^{- \frac{2}{3}} d x

y^{^{'}} = \frac{( x ^{2} + y )}{x ^{3}}

x \to 0 lim (x^{2} csc^{2} (2 x))

\int 2 sin (2 x) - 2 cos (2 x) d x

What is the derivative of f(x)=(5x)/((1+x^2)) ?
The derivative of f(x)=(5x)/((1+x^2)) is (5(1-x^2))/((1+x^2)^2)
What is the first derivative of f(x)=(5x)/((1+x^2)) ?
The first derivative of f(x)=(5x)/((1+x^2)) is (5(1-x^2))/((1+x^2)^2)