What is the solution for y^'=((x^2+y))/(x^3) ?

The solution for y^'=((x^2+y))/(x^3) is y=-(\Ei(1/(2x^2)))/(2e^{1/(2x^2))}+(c_{1})/(e^{1/(2x^2))}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

y^'=((x^2+y))/(x^3)

y^{^{'}} = \frac{( x ^{2} + y )}{x ^{3}}

y = - \frac{Ei ( \frac{1}{2 x ^{2}} )}{2 e ^{\frac{1}{2 x ^{2}}}} + \frac{c _{1}}{e ^{\frac{1}{2 x ^{2}}}}

Solution steps

y^{'} (x) = \frac{( x ^{2} + y )}{x ^{3}}

Solve linear ODE:

y = - \frac{Ei ( \frac{1}{2 x ^{2}} )}{2 e ^{\frac{1}{2 x ^{2}}}} + \frac{c _{1}}{e ^{\frac{1}{2 x ^{2}}}}

y = - \frac{Ei ( \frac{1}{2 x ^{2}} )}{2 e ^{\frac{1}{2 x ^{2}}}} + \frac{c _{1}}{e ^{\frac{1}{2 x ^{2}}}}

x \to 0 lim (x^{2} csc^{2} (2 x))

\int 2 sin (2 x) - 2 cos (2 x) d x

e^{x^{2} + 1}, 0

\int 2 e^{- 1.5 x} d x

\frac{d}{d x} (\frac{e ^{x}}{x - 1})

What is the solution for y^'=((x^2+y))/(x^3) ?
The solution for y^'=((x^2+y))/(x^3) is y=-(\Ei(1/(2x^2)))/(2e^{1/(2x^2))}+(c_{1})/(e^{1/(2x^2))}