What is maclaurin e^{x^2+1},0 ?

The answer to maclaurin e^{x^2+1},0 is e+ex^2+e/2 x^4+e/6 x^6+e/(24)x^8+\ldots

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

maclaurin e^{x^2+1},0

maclaurin

e^{x^{2} + 1}, 0

e + e x^{2} + \frac{e}{2} x^{4} + \frac{e}{6} x^{6} + \frac{e}{24} x^{8} + \dots

Solution steps

Apply the Maclaurin Formula

= e + \frac{\frac{d}{d x} ( e ^{x^{2} + 1} ) ( 0 )}{1 !} x + \frac{\frac{d ^{2}}{d x ^{2}} ( e ^{x^{2} + 1} ) ( 0 )}{2 !} x^{2} + \frac{\frac{d ^{3}}{d x ^{3}} ( e ^{x^{2} + 1} ) ( 0 )}{3 !} x^{3} + \dots

Evaluate Derivatives

= e + \frac{0}{1 !} x + \frac{2 e}{2 !} x^{2} + \frac{0}{3 !} x^{3} + \frac{12 e}{4 !} x^{4} + \frac{0}{5 !} x^{5} + \frac{120 e}{6 !} x^{6} + \frac{0}{7 !} x^{7} + \frac{1680 e}{8 !} x^{8} + \dots

Refine

= e + e x^{2} + \frac{e}{2} x^{4} + \frac{e}{6} x^{6} + \frac{e}{24} x^{8} + \dots

\int 2 e^{- 1.5 x} d x

\frac{d}{d x} (\frac{e ^{x}}{x - 1})

\frac{d}{d x} (cos^{5} (3 x))

\int sin (\frac{x}{3}) cos (\frac{2 x}{3}) d x

\int x (e^{x}) d x

What is maclaurin e^{x^2+1},0 ?
The answer to maclaurin e^{x^2+1},0 is e+ex^2+e/2 x^4+e/6 x^6+e/(24)x^8+\ldots