What is (d^2)/(dx^2)(sin(x)cos(x)) ?

The answer to (d^2)/(dx^2)(sin(x)cos(x)) is -sin(2x)*2

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(d^2)/(dx^2)(sin(x)cos(x))

\frac{d ^{2}}{d x ^{2}} (sin (x) cos (x))

- sin (2 x) \cdot 2

Solution steps

\frac{d ^{2}}{d x ^{2}} (sin (x) cos (x))

\frac{d}{d x} (sin (x) cos (x)) = cos (2 x)

= \frac{d}{d x} (cos (2 x))

\frac{d}{d x} (cos (2 x)) = - sin (2 x) \cdot 2

= - sin (2 x) \cdot 2

\int (\frac{( x - 3 )}{( x + 2 )}) d x

\frac{\partial}{\partial x} (9)

y^{^{'}} = a^{x + y}

\int \frac{x}{x - x ^{2}} d x

\frac{d y}{d x} = x^{2} y^{- 5}

What is (d^2)/(dx^2)(sin(x)cos(x)) ?
The answer to (d^2)/(dx^2)(sin(x)cos(x)) is -sin(2x)*2