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Popular >

y^'=a^{x+y}

Solution

y^{^{'}} = a^{x + y}

Solution

y = - \frac{ln ( - a ^{x} - c _{1} ln ( a ) )}{ln ( a )}

Solution steps

y^{'} (x) = a^{x + y}

Solve separable ODE:

y = - \frac{ln ( - a ^{x} - c _{1} ln ( a ) )}{ln ( a )}

y = - \frac{ln ( - a ^{x} - c _{1} ln ( a ) )}{ln ( a )}

Popular Examples

integral of x/(sqrt(x-x^2))

\int \frac{x}{x - x ^{2}} d x

(dy)/(dx)=x^2y^{-5}

\frac{d y}{d x} = x^{2} y^{- 5}

(2xy^2+3x^2)dx+(2x^2y)dy=0

(2 x y^{2} + 3 x^{2}) d x + (2 x^{2} y) d y = 0

derivative of (2x-5)(sqrt(x)+4)derivative of

(2 x - 5) (x + 4)

integral of 9-t^2

\int 9 - t^{2} d t

Frequently Asked Questions (FAQ)

What is the solution for y^'=a^{x+y} ?
The solution for y^'=a^{x+y} is y=-(ln(-a^x-c_{1}ln(a)))/(ln(a))