What is the integral from 1 to 2 of (2/(x^3)) ?

The integral from 1 to 2 of (2/(x^3)) is 3/4

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integral from 1 to 2 of (2/(x^3))

\int_{1}^{2} (\frac{2}{x ^{3}}) d x

\frac{3}{4}

Decimal Notation

0.75

Solution steps

\int_{1}^{2} \frac{2}{x ^{3}} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 2 \cdot \int_{1}^{2} \frac{1}{x ^{3}} d x

Apply the Power Rule

: [- \frac{1}{2 x ^{2}}]_{1}^{2}

= 2 [- \frac{1}{2 x ^{2}}]_{1}^{2}

Compute the boundaries:

\frac{3}{8}

= 2 \cdot \frac{3}{8}

Simplify

= \frac{3}{4}

f (x) = ln (x^{3} - 1)

x 64 - x^{2}, 0

\int - cos (\frac{x}{2}) d x

\frac{d}{d x} (x + \frac{7}{x})

\frac{d}{d x} ((x - 2 π)^{2})

What is the integral from 1 to 2 of (2/(x^3)) ?
The integral from 1 to 2 of (2/(x^3)) is 3/4