What is the tangent of 3x^2-4x ?

The tangent of 3x^2-4x is y=(6a_{0}-4)x-3a_{0}^2

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tangent of 3x^2-4x

tangent of

3 x^{2} - 4 x

y = (6 a_{0} - 4) x - 3 a_{0}^{2}

Solution steps

Compute the tangent line to the general point

x = a_{0}

Find the tangent point:

(a_{0}, 3 a_{0}^{2} - 4 a_{0})

Find the slope of

y = 3 x^{2} - 4 x : \frac{d y}{d x} = 6 x - 4

Compute the slope of

y = 3 x^{2} - 4 x

x = a_{0} : m = 6 a_{0} - 4

Find the line with slope m=

6 a_{0} - 4

and passing through

(a_{0}, 3 a_{0}^{2} - 4 a_{0}) : y = (6 a_{0} - 4) x - 3 a_{0}^{2}

y = (6 a_{0} - 4) x - 3 a_{0}^{2}

e^{x - 1}, 0

y + sin (x) = x^{3} y^{^{'}}

\int e^{4 y} d y

x \to 0 + lim (x^{6 x})

What is the tangent of 3x^2-4x ?
The tangent of 3x^2-4x is y=(6a_{0}-4)x-3a_{0}^2