What is the derivative of f(x)=sqrt(x)+\sqrt[3]{x} ?

The derivative of f(x)=sqrt(x)+\sqrt[3]{x} is 1/(2sqrt(x))+1/(3x^{2/3)}

What is the first derivative of f(x)=sqrt(x)+\sqrt[3]{x} ?

The first derivative of f(x)=sqrt(x)+\sqrt[3]{x} is 1/(2sqrt(x))+1/(3x^{2/3)}

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derivative of

\frac{1}{2 x} + \frac{1}{3 x ^{\frac{2}{3}}}

Solution steps

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

\frac{d}{d x} (x) = \frac{1}{2 x}

= \frac{1}{2 x} + \frac{1}{3 x ^{\frac{2}{3}}}

s

\int 400 - x^{2} d x

5 cos (3 x), 5 sin (6 x), [0, \frac{π}{6}]

cos (t + π)

2 x^{3} + 3 x^{2} - 12 x + 9

What is the derivative of f(x)=sqrt(x)+\sqrt[3]{x} ?
The derivative of f(x)=sqrt(x)+\sqrt[3]{x} is 1/(2sqrt(x))+1/(3x^{2/3)}
What is the first derivative of f(x)=sqrt(x)+\sqrt[3]{x} ?
The first derivative of f(x)=sqrt(x)+\sqrt[3]{x} is 1/(2sqrt(x))+1/(3x^{2/3)}