What is the integral of 5x^4-3x^2+7 ?

The integral of 5x^4-3x^2+7 is x^5-x^3+7x+C

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integral of 5x^4-3x^2+7

\int 5 x^{4} - 3 x^{2} + 7 d x

x^{5} - x^{3} + 7 x + C

Solution steps

\int 5 x^{4} - 3 x^{2} + 7 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int 5 x^{4} d x - \int 3 x^{2} d x + \int 7 d x

\int 5 x^{4} d x = x^{5}

\int 3 x^{2} d x = x^{3}

\int 7 d x = 7 x

= x^{5} - x^{3} + 7 x

Add a constant to the solution

= x^{5} - x^{3} + 7 x + C

x \to - 2.4 lim (x)

y^{^{'}} = \frac{2 y}{3 x}, y (27) = 4

\int \frac{x}{( x + 4 ) ( 2 x - 1 )} d x

\int 8 x - 1 d x

x cos (x^{3})

What is the integral of 5x^4-3x^2+7 ?
The integral of 5x^4-3x^2+7 is x^5-x^3+7x+C