What is the integral of x/((x+4)(2x-1)) ?

The integral of x/((x+4)(2x-1)) is 4/9 ln|x+4|+1/18 ln|2x-1|+C

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integral of x/((x+4)(2x-1))

\int \frac{x}{( x + 4 ) ( 2 x - 1 )} d x

\frac{4}{9} ln ∣ x + 4 ∣ + \frac{1}{18} ln ∣ 2 x - 1 ∣ + C

Solution steps

\int \frac{x}{( x + 4 ) ( 2 x - 1 )} d x

Take the partial fraction of

\frac{x}{( x + 4 ) ( 2 x - 1 )} : \frac{4}{9 ( x + 4 )} + \frac{1}{9 ( 2 x - 1 )}

= \int \frac{4}{9 ( x + 4 )} + \frac{1}{9 ( 2 x - 1 )} d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int \frac{4}{9 ( x + 4 )} d x + \int \frac{1}{9 ( 2 x - 1 )} d x

\int \frac{4}{9 ( x + 4 )} d x = \frac{4}{9} ln ∣ x + 4 ∣

\int \frac{1}{9 ( 2 x - 1 )} d x = \frac{1}{18} ln ∣ 2 x - 1 ∣

= \frac{4}{9} ln ∣ x + 4 ∣ + \frac{1}{18} ln ∣ 2 x - 1 ∣

Add a constant to the solution

= \frac{4}{9} ln ∣ x + 4 ∣ + \frac{1}{18} ln ∣ 2 x - 1 ∣ + C

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What is the integral of x/((x+4)(2x-1)) ?
The integral of x/((x+4)(2x-1)) is 4/9 ln|x+4|+1/18 ln|2x-1|+C