What is the integral of sin(y)sin(x) ?

The integral of sin(y)sin(x) is -sin(x)cos(y)+C

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integral of sin(y)sin(x)

\int sin (y) sin (x) d y

- sin (x) cos (y) + C

Solution steps

\int sin (y) sin (x) d y

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= sin (x) \cdot \int sin (y) d y

Use the common integral:

\int sin (y) d y = - cos (y)

= sin (x) (- cos (y))

Simplify

= - sin (x) cos (y)

Add a constant to the solution

= - sin (x) cos (y) + C

\int e^{l n (x + 2)} d x

y^{^{''}} + 1.9 \cdot y^{^{'}} = 0, y (0) = 0, y^{^{'}} (0) = 1

\int \frac{x}{x ^{2} + x - 1} d x

\frac{d}{d x} (sec (8 x^{3} + 1))

f (x) = 18 x, at x = 9

What is the integral of sin(y)sin(x) ?
The integral of sin(y)sin(x) is -sin(x)cos(y)+C