What is the integral of e^{ln(x+2)} ?

The integral of e^{ln(x+2)} is (x^2)/2+2x+C

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integral of e^{ln(x+2)}

\int e^{l n (x + 2)} d x

\frac{x ^{2}}{2} + 2 x + C

Solution steps

\int e^{l n (x + 2)} d x

Apply log rule:

a^{l o g_{a} (b)} = b

= \int x + 2 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int x d x + \int 2 d x

\int x d x = \frac{x ^{2}}{2}

\int 2 d x = 2 x

= \frac{x ^{2}}{2} + 2 x

Add a constant to the solution

= \frac{x ^{2}}{2} + 2 x + C

y^{^{''}} + 1.9 \cdot y^{^{'}} = 0, y (0) = 0, y^{^{'}} (0) = 1

\int \frac{x}{x ^{2} + x - 1} d x

\frac{d}{d x} (sec (8 x^{3} + 1))

f (x) = 18 x, at x = 9

n = 2 \sum \infty \frac{7}{4 ^{n}}

What is the integral of e^{ln(x+2)} ?
The integral of e^{ln(x+2)} is (x^2)/2+2x+C