What is the derivative of (x^2+x-2/(x-2)) ?

The derivative of (x^2+x-2/(x-2)) is (x^2-4x)/((x-2)^2)

What is the first derivative of (x^2+x-2/(x-2)) ?

The first derivative of (x^2+x-2/(x-2)) is (x^2-4x)/((x-2)^2)

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\frac{d}{d x} (\frac{x ^{2} + x - 2}{x - 2})

\frac{x ^{2} - 4 x}{( x - 2 ) ^{2}}

Solution steps

\frac{d}{d x} (\frac{x ^{2} + x - 2}{x - 2})

Apply the Quotient Rule:

(\frac{f}{g})^{'} = \frac{f ^{'} \cdot g - g ^{'} \cdot f}{g ^{2}}

= \frac{\frac{d}{d x} ( x ^{2} + x - 2 ) ( x - 2 ) - \frac{d}{d x} ( x - 2 ) ( x ^{2} + x - 2 )}{( x - 2 ) ^{2}}

\frac{d}{d x} (x^{2} + x - 2) = 2 x + 1

\frac{d}{d x} (x - 2) = 1

= \frac{( 2 x + 1 ) ( x - 2 ) - 1 \cdot ( x ^{2} + x - 2 )}{( x - 2 ) ^{2}}

Simplify

\frac{( 2 x + 1 ) ( x - 2 ) - 1 \cdot ( x ^{2} + x - 2 )}{( x - 2 ) ^{2}} : \frac{x ^{2} - 4 x}{( x - 2 ) ^{2}}

= \frac{x ^{2} - 4 x}{( x - 2 ) ^{2}}

\frac{\partial}{\partial x} (ln (x^{6} - y^{4}))

f (x) = 2 (x - 3)^{2} + 1, (4, 3)

\frac{d}{d t} (cos (\frac{t ^{3}}{10}))

x \to 2 lim (\frac{9 x}{x - 2})

\int x^{2} \cdot 3^{2 x} d x

What is the derivative of (x^2+x-2/(x-2)) ?
The derivative of (x^2+x-2/(x-2)) is (x^2-4x)/((x-2)^2)
What is the first derivative of (x^2+x-2/(x-2)) ?
The first derivative of (x^2+x-2/(x-2)) is (x^2-4x)/((x-2)^2)