What is the tangent of y=(1+5x)^{12},(0,1) ?

The tangent of y=(1+5x)^{12},(0,1) is y=60x+1

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tangent of y=(1+5x)^{12},(0,1)

tangent of

y = (1 + 5 x)^{12}, (0, 1)

y = 60 x + 1

Solution steps

Find the slope of

y = (1 + 5 x)^{12} : \frac{d y}{d x} = 60 (1 + 5 x)^{11}

Compute the slope of

y = (1 + 5 x)^{12}

(0, 1) : m = 60

Find the line with slope m=

60

and passing through

(0, 1) : y = 60 x + 1

y = 60 x + 1

x y^{^{'}} + 2 y = 2 e^{x}

\frac{d x}{d t} = sin (x)

\int e^{\frac{x}{16}} d x

\int x^{2} (x - 7) d x

\int x (2 x^{2} + 1)^{6} d x

What is the tangent of y=(1+5x)^{12},(0,1) ?
The tangent of y=(1+5x)^{12},(0,1) is y=60x+1