What is the integral of e^{x/(16)} ?

The integral of e^{x/(16)} is 16e^{x/(16)}+C

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integral of e^{x/(16)}

\int e^{\frac{x}{16}} d x

16 e^{\frac{x}{16}} + C

Solution steps

\int e^{\frac{x}{16}} d x

Apply u-substitution

: \int e^{u} \cdot 16 d u

= \int e^{u} \cdot 16 d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 16 \cdot \int e^{u} d u

Use the common integral:

\int e^{u} d u = e^{u}

= 16 e^{u}

Substitute back

u = \frac{x}{16}

= 16 e^{\frac{x}{16}}

Add a constant to the solution

= 16 e^{\frac{x}{16}} + C

\int x^{2} (x - 7) d x

\int x (2 x^{2} + 1)^{6} d x

t + 1

\frac{d}{d x} (\frac{2 x}{x + 9})

What is the integral of e^{x/(16)} ?
The integral of e^{x/(16)} is 16e^{x/(16)}+C