What is the first derivative of t+1 ?

The first derivative of t+1 is 1

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derivative of t+1

derivative of

t + 1

1

Solution steps

\frac{d}{d t} (t + 1)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d t}{d t} + \frac{d}{d t} (1)

\frac{d t}{d t} = 1

\frac{d}{d t} (1) = 0

= 1 + 0

Simplify

= 1

\frac{d}{d x} (\frac{2 x}{x + 9})

\frac{\partial}{\partial x} (8 - x^{2} + x y - 4 y^{2})

\int \frac{ln ( x )}{e ^{x}} d x

f (x) = x^{2} + 2 x + 1