What is the derivative of f(x)=x^2+2x+1 ?

The derivative of f(x)=x^2+2x+1 is 2x+2

What is the first derivative of f(x)=x^2+2x+1 ?

The first derivative of f(x)=x^2+2x+1 is 2x+2

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derivative of

f (x) = x^{2} + 2 x + 1

2 x + 2

Solution steps

\frac{d}{d x} (x^{2} + 2 x + 1)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{2}) + \frac{d}{d x} (2 x) + \frac{d}{d x} (1)

\frac{d}{d x} (x^{2}) = 2 x

\frac{d}{d x} (2 x) = 2

\frac{d}{d x} (1) = 0

= 2 x + 2 + 0

Simplify

= 2 x + 2

n = 1 \sum \infty \frac{x ^{n}}{8 ^{n}}

(x^{2} + 1)^{\frac{1}{2}}

sin (3 t)

\frac{\partial ^{2}}{\partial r \partial θ} (r (θ) sin (θ))

What is the derivative of f(x)=x^2+2x+1 ?
The derivative of f(x)=x^2+2x+1 is 2x+2
What is the first derivative of f(x)=x^2+2x+1 ?
The first derivative of f(x)=x^2+2x+1 is 2x+2