What is laplacetransform sin(3t) ?

The answer to laplacetransform sin(3t) is 3/(s^2+9)

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laplacetransform sin(3t)

laplace transform

sin (3 t)

\frac{3}{s ^{2} + 9}

Solution steps

L {sin (3 t)}

Use Laplace Transform table:

L {sin (a t)} = \frac{a}{s ^{2} + a ^{2}}

L {sin (3 t)} = \frac{3}{s ^{2} + 3 ^{2}}

= \frac{3}{s ^{2} + 3 ^{2}}

= \frac{3}{s ^{2} + 9}

\frac{\partial ^{2}}{\partial r \partial θ} (r (θ) sin (θ))

\int_{- 1}^{1} (x^{2} - 2 x) d x

\frac{d}{d x} (\frac{sin ( 2 x )}{cos ( x ^{2} )})

\int - \frac{1}{z ^{2}} d z

\frac{1}{4 s ^{3}} - \frac{5}{3 s ^{2}}

What is laplacetransform sin(3t) ?
The answer to laplacetransform sin(3t) is 3/(s^2+9)