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Popular >

integral of-1/(z^2)

Solution

\int - \frac{1}{z ^{2}} d z

Solution

\frac{1}{z} + C

Solution steps

\int - \frac{1}{z ^{2}} d z

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= - \int \frac{1}{z ^{2}} d z

Apply the Power Rule

: - \frac{1}{z}

= - (- \frac{1}{z})

Simplify

= \frac{1}{z}

Add a constant to the solution

= \frac{1}{z} + C

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Frequently Asked Questions (FAQ)

What is the integral of-1/(z^2) ?
The integral of-1/(z^2) is 1/z+C