What is the derivative of x^3-4x^2+1 ?

The derivative of x^3-4x^2+1 is 3x^2-8x

What is the first derivative of x^3-4x^2+1 ?

The first derivative of x^3-4x^2+1 is 3x^2-8x

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\frac{d}{d x} (x^{3} - 4 x^{2} + 1)

3 x^{2} - 8 x

Solution steps

\frac{d}{d x} (x^{3} - 4 x^{2} + 1)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{3}) - \frac{d}{d x} (4 x^{2}) + \frac{d}{d x} (1)

\frac{d}{d x} (x^{3}) = 3 x^{2}

\frac{d}{d x} (4 x^{2}) = 8 x

\frac{d}{d x} (1) = 0

= 3 x^{2} - 8 x + 0

Simplify

= 3 x^{2} - 8 x

\frac{\partial}{\partial y} (2 y^{2} e^{x y^{2}})

\frac{d}{d x} (ln ((2 x + 1)^{5}))

7 cos (x)

\int_{- \infty}^{0} x e^{- 8 x} d x

What is the derivative of x^3-4x^2+1 ?
The derivative of x^3-4x^2+1 is 3x^2-8x
What is the first derivative of x^3-4x^2+1 ?
The first derivative of x^3-4x^2+1 is 3x^2-8x