What is the sum from n=0 to infinity of 2n^2+1 ?

The sum from n=0 to infinity of 2n^2+1 is diverges

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sum from n=0 to infinity of 2n^2+1

n = 0 \sum \infty 2 n^{2} + 1

diverges

Solution steps

n = 0 \sum \infty 2 n^{2} + 1

Apply Series Divergence Test:

diverges

= diverges

(e^{t} sin (t))^{^{'}}

\frac{\partial}{\partial v} (u (v) (v)^{2 v} + e^{3})

y^{^{''}} - 4 y^{^{'}} + 4 y = 0, y (0) = - 2, y^{^{'}} (0) = 2

\frac{d}{d x} (x^{3} - 2 x^{2} + 1)

e^{(- 2 s)}

What is the sum from n=0 to infinity of 2n^2+1 ?
The sum from n=0 to infinity of 2n^2+1 is diverges