What is the integral from-1 to 1 of 1/(\sqrt[3]{x)} ?

The integral from-1 to 1 of 1/(\sqrt[3]{x)} is 0

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integral from-1 to 1 of 1/(\sqrt[3]{x)}

0

Solution steps

Find undefined (singularity) points:

x = 0

If exist

b, a < b < c, f (b) =

undefined

, \int_{a}^{c} f (x) d x = \int_{a}^{b} f (x) d x + \int_{b}^{c} f (x) d x

= - \frac{3 ( - 1 ) ^{\frac{2}{3}}}{2} + \frac{3}{2}

Simplify

- \frac{3 ( - 1 ) ^{\frac{2}{3}}}{2} + \frac{3}{2} : 0

= 0

n = 1 \sum \infty r^{n}

\frac{\partial}{\partial y} (x^{2} e^{yz})

\frac{d}{d x} (x^{2} + \frac{cos ( x )}{2})

\frac{d y}{d x} + \frac{1}{200 + 3 x} y = 12

f (x) = 6 x^{1.5} - 4 x^{0.5}

What is the integral from-1 to 1 of 1/(\sqrt[3]{x)} ?
The integral from-1 to 1 of 1/(\sqrt[3]{x)} is 0