What is the derivative of e^x+e^y ?

The derivative of e^x+e^y is e^x+e^y(dy)/(dx)

What is the first derivative of e^x+e^y ?

The first derivative of e^x+e^y is e^x+e^y(dy)/(dx)

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\frac{d}{d x} (e^{x} + e^{y})

e^{x} + e^{y} \frac{d y}{d x}

Solution steps

\frac{d}{d x} (e^{x} + e^{y})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (e^{x}) + \frac{d}{d x} (e^{y})

\frac{d}{d x} (e^{x}) = e^{x}

\frac{d}{d x} (e^{y}) = e^{y} \frac{d y}{d x}

= e^{x} + e^{y} \frac{d y}{d x}

\frac{d}{d x} (lo g_{10} (x^{2} + x + 1))

f (x) = \frac{2 x + 3}{3 x - 2}

\int_{0}^{2} \frac{1}{8 + 2 x ^{2}} d x

3 ln (x), x ln (x), 1, 2

\frac{d y}{d x} = - \frac{e ^{x}}{8}

What is the derivative of e^x+e^y ?
The derivative of e^x+e^y is e^x+e^y(dy)/(dx)
What is the first derivative of e^x+e^y ?
The first derivative of e^x+e^y is e^x+e^y(dy)/(dx)