What is (\partial)/(\partial y)(-cos(y)) ?

The answer to (\partial)/(\partial y)(-cos(y)) is sin(y)

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(\partial)/(\partial y)(-cos(y))

\frac{\partial}{\partial y} (- cos (y))

sin (y)

Solution steps

\frac{\partial}{\partial y} (- cos (y))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= - \frac{\partial}{\partial y} (cos (y))

Apply the common derivative:

\frac{\partial}{\partial y} (cos (y)) = - sin (y)

= - (- sin (y))

Simplify

= sin (y)

\frac{d}{d x} (0.1 \cdot x^{4})

cos (x) + sin (x) + \frac{1}{2} x^{2} + \frac{1}{x}

x \cdot e^{x}

\frac{d}{d t} (cos (120 π) t)

\int_{0}^{l} sin^{2} (\frac{nπ x}{l}) d x

What is (\partial)/(\partial y)(-cos(y)) ?
The answer to (\partial)/(\partial y)(-cos(y)) is sin(y)