What is the derivative of cos(x)+sin(x)+1/2 x^2+1/x ?

The derivative of cos(x)+sin(x)+1/2 x^2+1/x is -sin(x)+cos(x)+x-1/(x^2)

What is the first derivative of cos(x)+sin(x)+1/2 x^2+1/x ?

The first derivative of cos(x)+sin(x)+1/2 x^2+1/x is -sin(x)+cos(x)+x-1/(x^2)

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derivative of

cos (x) + sin (x) + \frac{1}{2} x^{2} + \frac{1}{x}

- sin (x) + cos (x) + x - \frac{1}{x ^{2}}

Solution steps

\frac{d}{d x} (cos (x) + sin (x) + \frac{1}{2} x^{2} + \frac{1}{x})

Simplify

cos (x) + sin (x) + \frac{1}{2} x^{2} + \frac{1}{x} : cos (x) + sin (x) + \frac{x ^{2}}{2} + \frac{1}{x}

= \frac{d}{d x} (cos (x) + sin (x) + \frac{x ^{2}}{2} + \frac{1}{x})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (cos (x)) + \frac{d}{d x} (sin (x)) + \frac{d}{d x} (\frac{x ^{2}}{2}) + \frac{d}{d x} (\frac{1}{x})

\frac{d}{d x} (cos (x)) = - sin (x)

\frac{d}{d x} (sin (x)) = cos (x)

\frac{d}{d x} (\frac{x ^{2}}{2}) = x

\frac{d}{d x} (\frac{1}{x}) = - \frac{1}{x ^{2}}

= - sin (x) + cos (x) + x - \frac{1}{x ^{2}}

x \cdot e^{x}

\frac{d}{d t} (cos (120 π) t)

\int_{0}^{l} sin^{2} (\frac{nπ x}{l}) d x

\int cos (1 - x) d x

\frac{d}{d x} (\frac{2}{( 1 - x ) ^{2}})

What is the derivative of cos(x)+sin(x)+1/2 x^2+1/x ?
The derivative of cos(x)+sin(x)+1/2 x^2+1/x is -sin(x)+cos(x)+x-1/(x^2)
What is the first derivative of cos(x)+sin(x)+1/2 x^2+1/x ?
The first derivative of cos(x)+sin(x)+1/2 x^2+1/x is -sin(x)+cos(x)+x-1/(x^2)