What is the derivative of 2/((1-x^2)) ?

The derivative of 2/((1-x^2)) is 4/((1-x)^3)

What is the first derivative of 2/((1-x^2)) ?

The first derivative of 2/((1-x^2)) is 4/((1-x)^3)

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\frac{d}{d x} (\frac{2}{( 1 - x ) ^{2}})

\frac{4}{( 1 - x ) ^{3}}

Solution steps

\frac{d}{d x} (\frac{2}{( 1 - x ) ^{2}})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 2 \frac{d}{d x} (\frac{1}{( 1 - x ) ^{2}})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= 2 \frac{d}{d x} ((1 - x)^{- 2})

Apply the chain rule:

- \frac{2}{( 1 - x ) ^{3}} \frac{d}{d x} (1 - x)

= - \frac{2}{( 1 - x ) ^{3}} \frac{d}{d x} (1 - x)

\frac{d}{d x} (1 - x) = - 1

= 2 (- \frac{2}{( 1 - x ) ^{3}} (- 1))

Simplify

2 (- \frac{2}{( 1 - x ) ^{3}} (- 1)) : \frac{4}{( 1 - x ) ^{3}}

= \frac{4}{( 1 - x ) ^{3}}

\int \frac{x ^{3} - 2}{x ^{2} + 3 x + 2} d x

\frac{d}{d x} (\frac{1}{x ^{3} - 2 x})

n \to \infty lim (- 1^{n})

\int_{0}^{π} 4 sin (x) + sin (4 x) d x

\frac{\partial}{\partial y} (1 - \frac{3}{x} + y)

What is the derivative of 2/((1-x^2)) ?
The derivative of 2/((1-x^2)) is 4/((1-x)^3)
What is the first derivative of 2/((1-x^2)) ?
The first derivative of 2/((1-x^2)) is 4/((1-x)^3)