What is the derivative of y=x^2e^x ?

The derivative of y=x^2e^x is 2xe^x+e^xx^2

What is the first derivative of y=x^2e^x ?

The first derivative of y=x^2e^x is 2xe^x+e^xx^2

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derivative of

y = x^{2} e^{x}

2 x e^{x} + e^{x} x^{2}

Solution steps

\frac{d}{d x} (x^{2} e^{x})

Apply the Product Rule:

(f \cdot g)^{'} = f^{'} \cdot g + f \cdot g^{'}

f = x^{2}, g = e^{x}

= \frac{d}{d x} (x^{2}) e^{x} + \frac{d}{d x} (e^{x}) x^{2}

\frac{d}{d x} (x^{2}) = 2 x

\frac{d}{d x} (e^{x}) = e^{x}

= 2 x e^{x} + e^{x} x^{2}

\int \frac{y ^{4} + 2 y ^{2} - 1}{y} d y

y = 5 - 7 x^{2}, (- 3, - 58)

\int t e^{3 t} - e^{t} d t

\int \frac{1}{x ^{2} - 12} d x

\int \frac{1}{x 25 x ^{2} - 25} d x

What is the derivative of y=x^2e^x ?
The derivative of y=x^2e^x is 2xe^x+e^xx^2
What is the first derivative of y=x^2e^x ?
The first derivative of y=x^2e^x is 2xe^x+e^xx^2