What is the tangent of y=5-7x^2,(-3,-58) ?

The tangent of y=5-7x^2,(-3,-58) is y=42x+68

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tangent of y=5-7x^2,(-3,-58)

tangent of

y = 5 - 7 x^{2}, (- 3, - 58)

y = 42 x + 68

Solution steps

Find the slope of

y = 5 - 7 x^{2} : \frac{d y}{d x} = - 14 x

Compute the slope of

y = 5 - 7 x^{2}

(- 3, - 58) : m = 42

Find the line with slope m=

42

and passing through

(- 3, - 58) : y = 42 x + 68

y = 42 x + 68

\int t e^{3 t} - e^{t} d t

\int \frac{1}{x ^{2} - 12} d x

\int \frac{1}{x 25 x ^{2} - 25} d x

x \to - 5.8 lim (ln (x^{2} - 9))

n = 1 \sum \infty \frac{n ^{2}}{n ^{3}}

What is the tangent of y=5-7x^2,(-3,-58) ?
The tangent of y=5-7x^2,(-3,-58) is y=42x+68