What is the limit as x approaches-5.8 of ln(x^2-9) ?

The limit as x approaches-5.8 of ln(x^2-9) is 3.20437…

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limit as x approaches-5.8 of ln(x^2-9)

x \to - 5.8 lim (ln (x^{2} - 9))

3.20437 \dots

Solution steps

x \to - 5.8 lim (ln (x^{2} - 9))

Plug in the value

x = - 5.8

= ln ((- 5.8)^{2} - 9)

Simplify

ln ((- 5.8)^{2} - 9) : 3.20437 \dots

= 3.20437 \dots

n = 1 \sum \infty \frac{n ^{2}}{n ^{3}}

\frac{1}{4} x

(e^{t} cos (t))^{^{'}}

\frac{\partial}{\partial y} (y^{2} - x)

\frac{\partial}{\partial z} (x + y)

What is the limit as x approaches-5.8 of ln(x^2-9) ?
The limit as x approaches-5.8 of ln(x^2-9) is 3.20437…