What is the derivative of f(x)=6e^x+4/(\sqrt[3]{x)} ?

The derivative of f(x)=6e^x+4/(\sqrt[3]{x)} is 6e^x-4/(3x^{4/3)}

What is the first derivative of f(x)=6e^x+4/(\sqrt[3]{x)} ?

The first derivative of f(x)=6e^x+4/(\sqrt[3]{x)} is 6e^x-4/(3x^{4/3)}

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derivative of

6 e^{x} - \frac{4}{3 x ^{\frac{4}{3}}}

Solution steps

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

\frac{d}{d x} (6 e^{x}) = 6 e^{x}

= 6 e^{x} - \frac{4}{3 x ^{\frac{4}{3}}}

\frac{\partial}{\partial x} (5 x^{2} - 3 x y^{2} + x yz)

\int - \frac{1}{1 + u ^{2}} d u

3 e^{- 3 s}

x^{2} y^{^{'}} + 2 x y = 19 cos^{2} (x)

y^{^{''}} + 8 y^{^{'}} - 9 y = 0, y (1) = 1, y^{^{'}} (1) = 0

What is the derivative of f(x)=6e^x+4/(\sqrt[3]{x)} ?
The derivative of f(x)=6e^x+4/(\sqrt[3]{x)} is 6e^x-4/(3x^{4/3)}
What is the first derivative of f(x)=6e^x+4/(\sqrt[3]{x)} ?
The first derivative of f(x)=6e^x+4/(\sqrt[3]{x)} is 6e^x-4/(3x^{4/3)}