What is the derivative of x^3+3x ?

The derivative of x^3+3x is 3x^2+3

What is the first derivative of x^3+3x ?

The first derivative of x^3+3x is 3x^2+3

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\frac{d}{d x} (x^{3} + 3 x)

3 x^{2} + 3

Solution steps

\frac{d}{d x} (x^{3} + 3 x)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{3}) + \frac{d}{d x} (3 x)

\frac{d}{d x} (x^{3}) = 3 x^{2}

\frac{d}{d x} (3 x) = 3

= 3 x^{2} + 3

\frac{d}{d x} ((\frac{1}{x ^{2}} - \frac{9}{x ^{4}}) (x + 3 x^{3}))

\int_{- 2}^{2} 4 - x^{2} d x

\int_{0}^{3} 4 - x d x

\frac{d y}{d x} = \frac{x e ^{2 x}}{x + k}

y^{^{''}} + 2 y^{^{'}} + 14 y = 0, y (0) = 1, y^{^{'}} (0) = 0

What is the derivative of x^3+3x ?
The derivative of x^3+3x is 3x^2+3
What is the first derivative of x^3+3x ?
The first derivative of x^3+3x is 3x^2+3