What is (\partial)/(\partial x)(2xln(xy)) ?

The answer to (\partial)/(\partial x)(2xln(xy)) is 2(ln(xy)+1)

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(\partial)/(\partial x)(2xln(xy))

\frac{\partial}{\partial x} (2 x ln (x y))

2 (ln (x y) + 1)

Solution steps

\frac{\partial}{\partial x} (2 x ln (x y))

Treat

y

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 2 \frac{\partial}{\partial x} (x ln (x y))

Apply the Product Rule:

(f \cdot g)^{'} = f^{'} \cdot g + f \cdot g^{'}

f = x, g = ln (x y)

= 2 (\frac{\partial}{\partial x} (x) ln (x y) + \frac{\partial}{\partial x} (ln (x y)) x)

\frac{\partial}{\partial x} (x) = 1

\frac{\partial}{\partial x} (ln (x y)) = \frac{1}{x}

= 2 (1 \cdot ln (x y) + \frac{1}{x} x)

Simplify

2 (1 \cdot ln (x y) + \frac{1}{x} x) : 2 (ln (x y) + 1)

= 2 (ln (x y) + 1)

\int_{0}^{50} 0.624 x d x

3 x, 4 - x^{2}

3 e^{2 x} (\frac{d y}{d x}) = - 4 (\frac{x}{y ^{2}})

What is (\partial)/(\partial x)(2xln(xy)) ?
The answer to (\partial)/(\partial x)(2xln(xy)) is 2(ln(xy)+1)