What is the derivative of 1/(\sqrt[5]{2x-1}) ?

The derivative of 1/(\sqrt[5]{2x-1}) is -2/(5(2x-1)^{6/5)}

What is the first derivative of 1/(\sqrt[5]{2x-1}) ?

The first derivative of 1/(\sqrt[5]{2x-1}) is -2/(5(2x-1)^{6/5)}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

- \frac{2}{5 ( 2 x - 1 ) ^{\frac{6}{5}}}

Solution steps

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= \frac{d}{d x} ((2 x - 1)^{- \frac{1}{5}})

Apply the chain rule:

- \frac{1}{5 ( 2 x - 1 ) ^{\frac{6}{5}}} \frac{d}{d x} (2 x - 1)

= - \frac{1}{5 ( 2 x - 1 ) ^{\frac{6}{5}}} \frac{d}{d x} (2 x - 1)

\frac{d}{d x} (2 x - 1) = 2

= - \frac{1}{5 ( 2 x - 1 ) ^{\frac{6}{5}}} \cdot 2

Simplify

- \frac{1}{5 ( 2 x - 1 ) ^{\frac{6}{5}}} \cdot 2 : - \frac{2}{5 ( 2 x - 1 ) ^{\frac{6}{5}}}

= - \frac{2}{5 ( 2 x - 1 ) ^{\frac{6}{5}}}

4 y^{^{''}} + 26 y = 0

y = 5 x

\int (3 x^{2} - 6 x - 7) d x

\frac{1}{( s ^{2} - 4 s + 5 )}

\frac{d}{d x} (sin (3 x) + 3 x cos (3 x))

What is the derivative of 1/(\sqrt[5]{2x-1}) ?
The derivative of 1/(\sqrt[5]{2x-1}) is -2/(5(2x-1)^{6/5)}
What is the first derivative of 1/(\sqrt[5]{2x-1}) ?
The first derivative of 1/(\sqrt[5]{2x-1}) is -2/(5(2x-1)^{6/5)}