What is the integral of (3x^2-6x-7) ?

The integral of (3x^2-6x-7) is x^3-3x^2-7x+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral of (3x^2-6x-7)

\int (3 x^{2} - 6 x - 7) d x

x^{3} - 3 x^{2} - 7 x + C

Solution steps

\int 3 x^{2} - 6 x - 7 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int 3 x^{2} d x - \int 6 x d x - \int 7 d x

\int 3 x^{2} d x = x^{3}

\int 6 x d x = 3 x^{2}

\int 7 d x = 7 x

= x^{3} - 3 x^{2} - 7 x

Add a constant to the solution

= x^{3} - 3 x^{2} - 7 x + C

\frac{1}{( s ^{2} - 4 s + 5 )}

\frac{d}{d x} (sin (3 x) + 3 x cos (3 x))

\frac{d}{d x} (x - e^{- x})

\int (3 x + 2)^{2.4} d x

\frac{\partial}{\partial x} (x^{6} y - 2 x^{5} y^{2})

What is the integral of (3x^2-6x-7) ?
The integral of (3x^2-6x-7) is x^3-3x^2-7x+C