What is x^2+2y^2-2x-8y+6=0(0.3) ?

The solution to x^2+2y^2-2x-8y+6=0(0.3) is Ellipse with (h,k)=(1,2),a=sqrt(3),b=sqrt(3/2)

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x^2+2y^2-2x-8y+6=0(0.3)

x^{2} + 2 y^{2} - 2 x - 8 y + 6 = 0 (0.3)

(h, k) = (1, 2), a = 3, b = \frac{3}{2}

Solution steps

x^{2} + 2 y^{2} - 2 x - 8 y + 6 = 0 \cdot 0.3

Rewrite

x^{2} + 2 y^{2} - 2 x - 8 y + 6 = 00.3

in the form of the standard ellipse equation

\frac{( x - 1 ) ^{2}}{( 3 ) ^{2}} + \frac{( y - 2 ) ^{2}}{( \frac{3}{2} ) ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (1, 2), a = 3, b = \frac{3}{2}

a > b

therefore

a

is semi-major axis and

b

is semi-minor axis

Ellipse with center (h, k) = (1, 2), a = 3, b = \frac{3}{2}

\frac{1}{2 s ^{2} + 1}

\int_{0}^{2} \frac{1}{x ^{2} - 7 x + 6} d x

\int \frac{36 x ^{2} - 49}{x ^{3}} d x

x \to \frac{π}{2} - lim (sec (x))

\frac{d y}{d x} = e^{8 x - 3 y}, y (0) = 4

What is x^2+2y^2-2x-8y+6=0(0.3) ?
The solution to x^2+2y^2-2x-8y+6=0(0.3) is Ellipse with (h,k)=(1,2),a=sqrt(3),b=sqrt(3/2)