What is the tangent of f(x)=3x-2sqrt(x),(1,1) ?

The tangent of f(x)=3x-2sqrt(x),(1,1) is y=2x-1

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tangent of f(x)=3x-2sqrt(x),(1,1)

tangent of

f (x) = 3 x - 2 x, (1, 1)

y = 2 x - 1

Solution steps

Find the slope of

f (x) = 3 x - 2 x : \frac{df ( x )}{d x} = 3 - \frac{1}{x}

Compute the slope of

f (x) = 3 x - 2 x

(1, 1) : m = 2

Find the line with slope m=

2

and passing through

(1, 1) : y = 2 x - 1

y = 2 x - 1

z \to + 10 lim (\frac{1}{z - 10})

- 5 csc (x) + sec (x)

2 ln (3 x)

\int \frac{x}{( x ^{2} + y ^{2} )} d x

x^{3} - 2 x + 1

What is the tangent of f(x)=3x-2sqrt(x),(1,1) ?
The tangent of f(x)=3x-2sqrt(x),(1,1) is y=2x-1