What is the integral of 1+cos(2x) ?

The integral of 1+cos(2x) is x+1/2 sin(2x)+C

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integral of 1+cos(2x)

\int 1 + cos (2 x) d x

x + \frac{1}{2} sin (2 x) + C

Solution steps

\int 1 + cos (2 x) d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int 1 d x + \int cos (2 x) d x

\int 1 d x = x

\int cos (2 x) d x = \frac{1}{2} sin (2 x)

= x + \frac{1}{2} sin (2 x)

Add a constant to the solution

= x + \frac{1}{2} sin (2 x) + C

n = 1 \sum \infty (\frac{1}{2})^{99 - 1}

\int \frac{7 x}{( 1 - 4 x ) ^{4}} d x

\int x^{2} \cdot sin (a x) d x

\frac{\partial}{\partial y} (e^{- 3 x} cos (3 y))

f (x) = ln (1 - x)

What is the integral of 1+cos(2x) ?
The integral of 1+cos(2x) is x+1/2 sin(2x)+C