What is the derivative of f(x)=ln(1-x) ?

The derivative of f(x)=ln(1-x) is -1/(1-x)

What is the first derivative of f(x)=ln(1-x) ?

The first derivative of f(x)=ln(1-x) is -1/(1-x)

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derivative of

f (x) = ln (1 - x)

- \frac{1}{1 - x}

Solution steps

\frac{d}{d x} (ln (1 - x))

Apply the chain rule:

\frac{1}{1 - x} \frac{d}{d x} (1 - x)

= \frac{1}{1 - x} \frac{d}{d x} (1 - x)

\frac{d}{d x} (1 - x) = - 1

= \frac{1}{1 - x} (- 1)

Simplify

= - \frac{1}{1 - x}

y^{^{'}} = - k y^{\frac{1}{2}}

\frac{d}{d x} (\frac{4}{3} x^{\frac{3}{2}})

\int csc^{4} (x) d x

cos^{l n (7 x)} (x)

\int \frac{x - 3}{( 5 - 4 x - x ^{2} ) ^{\frac{3}{2}}} d x

What is the derivative of f(x)=ln(1-x) ?
The derivative of f(x)=ln(1-x) is -1/(1-x)
What is the first derivative of f(x)=ln(1-x) ?
The first derivative of f(x)=ln(1-x) is -1/(1-x)