What is the derivative of x+x^2+x^3 ?

The derivative of x+x^2+x^3 is 1+2x+3x^2

What is the first derivative of x+x^2+x^3 ?

The first derivative of x+x^2+x^3 is 1+2x+3x^2

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\frac{d}{d x} (x + x^{2} + x^{3})

1 + 2 x + 3 x^{2}

Solution steps

\frac{d}{d x} (x + x^{2} + x^{3})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d x}{d x} + \frac{d}{d x} (x^{2}) + \frac{d}{d x} (x^{3})

\frac{d x}{d x} = 1

\frac{d}{d x} (x^{2}) = 2 x

\frac{d}{d x} (x^{3}) = 3 x^{2}

= 1 + 2 x + 3 x^{2}

\frac{\partial}{\partial x} (sin (y) - cos (x))

y = \frac{1}{x}, y = \frac{1}{x ^{2}}, x = 5

\frac{d}{d x} (- 3 x^{4} + 2 y^{2})

\frac{2 x + 1}{4 x ^{2} + 1}

\int x cos (a x) d x

What is the derivative of x+x^2+x^3 ?
The derivative of x+x^2+x^3 is 1+2x+3x^2
What is the first derivative of x+x^2+x^3 ?
The first derivative of x+x^2+x^3 is 1+2x+3x^2