What is the limit as x approaches 2 of 4x^2+x-4 ?

The limit as x approaches 2 of 4x^2+x-4 is 14

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limit as x approaches 2 of 4x^2+x-4

x \to 2 lim (4 x^{2} + x - 4)

14

Solution steps

x \to 2 lim (4 x^{2} + x - 4)

Plug in the value

x = 2

= 4 \cdot 2^{2} + 2 - 4

Simplify

= 14

f (t) = cos (4 t)

arcsin (8 x + 1)

t^{2} (6 t + 5)^{3}

\frac{d}{d x} (\frac{( 2 x - 1 )}{x ^{2}})

\int_{0}^{18} x 18 - x d x

What is the limit as x approaches 2 of 4x^2+x-4 ?
The limit as x approaches 2 of 4x^2+x-4 is 14