What is the derivative of arcsin(8x+1) ?

The derivative of arcsin(8x+1) is 2/(sqrt(-x(4x+1)))

What is the first derivative of arcsin(8x+1) ?

The first derivative of arcsin(8x+1) is 2/(sqrt(-x(4x+1)))

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

derivative of

arcsin (8 x + 1)

\frac{2}{- x ( 4 x + 1 )}

Solution steps

\frac{d}{d x} (arcsin (8 x + 1))

Apply the chain rule:

\frac{1}{1 - ( 8 x + 1 ) ^{2}} \frac{d}{d x} (8 x + 1)

= \frac{1}{1 - ( 8 x + 1 ) ^{2}} \frac{d}{d x} (8 x + 1)

\frac{d}{d x} (8 x + 1) = 8

= \frac{1}{1 - ( 8 x + 1 ) ^{2}} \cdot 8

Simplify

\frac{1}{1 - ( 8 x + 1 ) ^{2}} \cdot 8 : \frac{2}{- x ( 4 x + 1 )}

= \frac{2}{- x ( 4 x + 1 )}

t^{2} (6 t + 5)^{3}

\frac{d}{d x} (\frac{( 2 x - 1 )}{x ^{2}})

\int_{0}^{18} x 18 - x d x

\frac{1}{( s - 2 )}

What is the derivative of arcsin(8x+1) ?
The derivative of arcsin(8x+1) is 2/(sqrt(-x(4x+1)))
What is the first derivative of arcsin(8x+1) ?
The first derivative of arcsin(8x+1) is 2/(sqrt(-x(4x+1)))