What is inverse oflaplace 1/((s-2)) ?

The answer to inverse oflaplace 1/((s-2)) is e^{2t}

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inverse oflaplace 1/((s-2))

inverse laplace

\frac{1}{( s - 2 )}

e^{2 t}

Solution steps

L^{- 1} {\frac{1}{( s - 2 )}}

Use Inverse Laplace Transform table:

L^{- 1} {\frac{1}{s - a}} = e^{a t}

L^{- 1} {\frac{1}{s - 2}} = e^{2 t}

= e^{2 t}

\frac{d}{d x} (\frac{x}{x + 4})

\int \frac{1 + e ^{2 x}}{e ^{x - 1}} d x

\int 1 - \frac{3}{14 - x} d x

\int \frac{3}{x + 3 + x} d x

What is inverse oflaplace 1/((s-2)) ?
The answer to inverse oflaplace 1/((s-2)) is e^{2t}