What is the derivative of 8x^3-cos(4x) ?

The derivative of 8x^3-cos(4x) is 24x^2+4sin(4x)

What is the first derivative of 8x^3-cos(4x) ?

The first derivative of 8x^3-cos(4x) is 24x^2+4sin(4x)

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\frac{d}{d x} (8 x^{3} - cos (4 x))

24 x^{2} + 4 sin (4 x)

Solution steps

\frac{d}{d x} (8 x^{3} - cos (4 x))

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (8 x^{3}) - \frac{d}{d x} (cos (4 x))

\frac{d}{d x} (8 x^{3}) = 24 x^{2}

\frac{d}{d x} (cos (4 x)) = - sin (4 x) \cdot 4

= 24 x^{2} - (- sin (4 x) \cdot 4)

Simplify

= 24 x^{2} + 4 sin (4 x)

\int x + \frac{1}{x} - 7 d x

\frac{d}{d x} (e^{- x} cos (y) - e^{- y} cos (x))

x \to 3 - lim (3 - ln (\frac{1}{3 - x}))

y^{^{'}} = (2 - y) y

x \to 7 lim (5 x^{2} - 5 x + 6)

What is the derivative of 8x^3-cos(4x) ?
The derivative of 8x^3-cos(4x) is 24x^2+4sin(4x)
What is the first derivative of 8x^3-cos(4x) ?
The first derivative of 8x^3-cos(4x) is 24x^2+4sin(4x)