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Popular >

y^'=(2-y)y

Solution

y^{^{'}} = (2 - y) y

Solution

y = \frac{2}{- e ^{- 2 t - c_{1}} + 1}

Solution steps

y^{'} (t) = (2 - y) y

Solve Bernoulli ODE:

y = \frac{2}{- e ^{- 2 t - c_{1}} + 1}

y = \frac{2}{- e ^{- 2 t - c_{1}} + 1}

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\int cos^{5} (2 x) d x

derivative of x^{1-n}

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Frequently Asked Questions (FAQ)

What is the solution for y^'=(2-y)y ?
The solution for y^'=(2-y)y is y= 2/(-e^{-2t-c_{1)}+1}