What is the derivative of y=3e^{4x} ?

The derivative of y=3e^{4x} is 12e^{4x}

What is the first derivative of y=3e^{4x} ?

The first derivative of y=3e^{4x} is 12e^{4x}

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derivative of

y = 3 e^{4 x}

12 e^{4 x}

Solution steps

\frac{d}{d x} (3 e^{4 x})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 3 \frac{d}{d x} (e^{4 x})

Apply the chain rule:

e^{4 x} \frac{d}{d x} (4 x)

= e^{4 x} \frac{d}{d x} (4 x)

\frac{d}{d x} (4 x) = 4

= 3 e^{4 x} \cdot 4

Simplify

= 12 e^{4 x}

\int 6 x^{2} \cdot e^{x^{3}} d x

\int \frac{x ^{2} + x + 1}{( x + 1 ) ^{2} ( x + 2 )} d x

\frac{d}{d x} ((x cos (x)) (cos (x) + tan (x)))

\int_{0}^{1} 1 - x^{\frac{2}{7}} d x

x^{2} - 3 x y + x y^{^{'}} = 0

What is the derivative of y=3e^{4x} ?
The derivative of y=3e^{4x} is 12e^{4x}
What is the first derivative of y=3e^{4x} ?
The first derivative of y=3e^{4x} is 12e^{4x}