What is the solution for 7y^'+y=5t^2 ?

The solution for 7y^'+y=5t^2 is y=5(t^2-14(t-7))+(c_{1})/(e^{t/7)}

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7y^'+y=5t^2

7 y^{^{'}} + y = 5 t^{2}

y = 5 (t^{2} - 14 (t - 7)) + \frac{c _{1}}{e ^{\frac{t}{7}}}

Solution steps

7 y^{'} (t) + y = 5 t^{2}

Solve linear ODE:

y = 5 (t^{2} - 14 (t - 7)) + \frac{c _{1}}{e ^{\frac{t}{7}}}

y = 5 (t^{2} - 14 (t - 7)) + \frac{c _{1}}{e ^{\frac{t}{7}}}

\frac{d}{d x} (e^{x^{3} - x})

n = 0 \sum \infty e^{- \frac{3 n}{2}}

\frac{d}{d x _{0}} (x_{0})

x \to 2 lim (e^{\frac{3}{2 - x}})

\int 4 x^{2} + 2 + \frac{5}{x ^{2} + 1} d x

What is the solution for 7y^'+y=5t^2 ?
The solution for 7y^'+y=5t^2 is y=5(t^2-14(t-7))+(c_{1})/(e^{t/7)}