What is (\partial)/(\partial t)(3arcsin(t)) ?

The answer to (\partial)/(\partial t)(3arcsin(t)) is 3/(sqrt(1-t^2))

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(\partial)/(\partial t)(3arcsin(t))

\frac{\partial}{\partial t} (3 arcsin (t))

\frac{3}{1 - t ^{2}}

Solution steps

\frac{\partial}{\partial t} (3 arcsin (t))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 3 \frac{\partial}{\partial t} (arcsin (t))

Apply the common derivative:

\frac{\partial}{\partial t} (arcsin (t)) = \frac{1}{1 - t ^{2}}

= 3 \cdot \frac{1}{1 - t ^{2}}

Simplify

3 \cdot \frac{1}{1 - t ^{2}} : \frac{3}{1 - t ^{2}}

= \frac{3}{1 - t ^{2}}

\frac{d y}{d x} = - (1 + y)^{4}

\frac{d}{d x} (\frac{1}{2} x + 4)

\frac{\partial}{\partial y} (2 x y + 3 y)

\int 2 x + 1 d x

\int x^{2} x^{3 + 1} d x

What is (\partial)/(\partial t)(3arcsin(t)) ?
The answer to (\partial)/(\partial t)(3arcsin(t)) is 3/(sqrt(1-t^2))